Please Quickly!!!!!

[waqas_mlk]

Umeed hy sab khairiat sy hon gy.....plz mujay kuch iota (i) ky baray may detail chaaeythi ahgar kisi ko pata hy ya xi ki mathematics ki book ki link hy to share me.........

[*Noor-ul-Ain*]

iota = root of -1

so iota ^iota = e^((pi/2)i *i) = e^(-pi/2)

this is one of the values but it is multivalued

i = e^(pi/2+2npi) so i^i = e^(-pi/2 + 2npi) n is from - infinite to + infiinite