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Thread: Simple Guessing game in C++

  1. #1
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    Default Simple Guessing game in C++

    #include<iostream.h>
    #include<conio.h>

    main ()
    {
    cout<<"********Guessing Game********\n********{1 to 100}********\n";
    int number, i = 1;
    int guess = 46; //any number you give
    char op;
    do{
    while (i<=5)
    {

    cout<<"Guess the number? ";
    cin>> number;
    if(number == guess) {cout<<"Congratulations!!! You Won.\n";break;}i++;
    if(number < guess) {cout<<"Sorry: Your guess is small\n";continue;}
    else {cout<<"sorry your guess is large.\n";continue;}

    }
    if(i==6)
    cout<<"Sorry Your tries finish";
    cout<<"Do you want to p lay again[y/n]? ";cin>>op;
    }
    while(op =='y');

    }

  2. #2
    RanaFaheemAg's Avatar
    RanaFaheemAg is offline Senior Member+
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    Default

    nice

  3. #3
    shanibaba54 is offline Junior Member
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    Nice, I think it is related to virtual University's assignment.

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    main ye game kese chalaun mene nam apna programari rakha he par mujhe programing bilkul nahi aati mujhe bataiye kese isko compile karun karun aur run karun

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    Inam__NiaZ's Avatar
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    Default

    Nice job

  6. #6
    sabinkarim's Avatar
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    Thanks a lot.

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    khan arbab's Avatar
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    Nice

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    bilalajk's Avatar
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    kya bt

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    arslan659 is offline Junior Member
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    nice bro

  10. #10
    Arsalan 0.1's Avatar
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    nyc

  11. #11
    Z.Programmer is offline Member
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    Quote Ahsan ANC said: View Post
    #include<iostream.h>
    #include<conio.h>

    main ()
    {
    cout<<"********Guessing Game********\n********{1 to 100}********\n";
    int number, i = 1;
    int guess = 46; //any number you give
    char op;
    do{
    while (i<=5)
    {

    cout<<"Guess the number? ";
    cin>> number;
    if(number == guess) {cout<<"Congratulations!!! You Won.\n";break;}i++;
    if(number < guess) {cout<<"Sorry: Your guess is small\n";continue;}
    else {cout<<"sorry your guess is large.\n";continue;}

    }
    if(i==6)
    cout<<"Sorry Your tries finish";
    cout<<"Do you want to p lay again[y/n]? ";cin>>op;
    }
    while(op =='y');

    }
    Try to warp your coding. Then it will be more easy to understand.
    Last edited by Z.Programmer; 29th February 2016 at 08:55 PM.

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