A>b=b<a

[mohammadhanif14]

if

A = 75.00 Dirhams x (70 grams x 100 cans)
what is the price of 1 gram?

B = 53.70 Dirhams x (48 grams x 135 cans)
what is the price of 1 gram?

and we have to prove that A>B and B<A.

sloution:

A = 100 cans
1 can = 70 grams
= price of A = 100 x 70 = 7000
price of 1 gram = total amount / total weight
price of 1 gram = 75 / 70000
price of 1 gram = 0.0107142857142857

now to prove that the price of 1 gram is = 0.0107142857142857,
0.0107142857142857 x the total weight
0.0107142857142857 x 7000
= 75
so the price of 1 gram is = 0.0107142857142857
================================================== =
B= 48 cans
1 can = 135 grams
= price of B= 48 x 135 = 6480
price of 1 gram = total amount / total weight
price of 1 gram = 53.70 / 6480
price of 1 gram = 0.008287037037037

now to prove that the price of 1 gram is = 0.008287037037037,
0.008287037037037 x the total weight
0.008287037037037 x 7000
= 53.70
so the price of 1 gram is = 0.008287037037037

so the value of A is greater than B
because A = 0.0107142857142857
B = 0.008287037037037

now 0.010 is greater than 0.008
A = 0.010
B = 0.008

the price of 1 gram in A is expensive than B
so A>B and B<A

[27usman]

bhai baat aik hi hai jo apko itd per solution diya gya tha wo b yehi tha...bs apny kuch ziada hi detail sy kiya hai or formal and bookish way ma kiya hai...jaisay choti classes ma krty hain.....masters walay to shortcut hi dhondty hain....
ap ny jis method sy kiya hai isko unitry method kehty hain...